How do you find the product #(p+2)(p-10)#?

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Answer 1 · 2018-03-13T12:43:56

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(p) + color(red)(2))(color(blue)(p) - color(blue)(10))# becomes:

#(color(red)(p) xx color(blue)(p)) - (color(red)(p) xx color(blue)(10)) + (color(red)(2) xx color(blue)(p)) - (color(red)(2) xx color(blue)(10))#

#p^2 - 10p + 2p - 20#

We can now combine like terms:

#p^2 + (-10 + 2)p - 20#

#p^2 + (-8)p - 20#

#p^2 - 8p - 20#

Answer 2 · 2018-03-13T12:47:43

Using distributive property of product regarding the sum. See below

#(p+2)(p-10)=p(p-10)+2(p-10)=p^2-10p+2p-20=p^2-8p-20#