# How do you find the product (p+2)(p-10)?

Mar 13, 2018

See a solution process below:

#### Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$\left(\textcolor{red}{p} + \textcolor{red}{2}\right) \left(\textcolor{b l u e}{p} - \textcolor{b l u e}{10}\right)$ becomes:

$\left(\textcolor{red}{p} \times \textcolor{b l u e}{p}\right) - \left(\textcolor{red}{p} \times \textcolor{b l u e}{10}\right) + \left(\textcolor{red}{2} \times \textcolor{b l u e}{p}\right) - \left(\textcolor{red}{2} \times \textcolor{b l u e}{10}\right)$

${p}^{2} - 10 p + 2 p - 20$

We can now combine like terms:

${p}^{2} + \left(- 10 + 2\right) p - 20$

${p}^{2} + \left(- 8\right) p - 20$

${p}^{2} - 8 p - 20$

Mar 13, 2018

Using distributive property of product regarding the sum. See below

#### Explanation:

$\left(p + 2\right) \left(p - 10\right) = p \left(p - 10\right) + 2 \left(p - 10\right) = {p}^{2} - 10 p + 2 p - 20 = {p}^{2} - 8 p - 20$