# How do you find the quotient (4y-8)/(y+1)div(y-2)?

May 27, 2017

$\frac{4 y - 8}{y + 1} \div \left(y - 2\right) = \frac{4}{y + 1}$

#### Explanation:

To do this problem we need to simplify the top or the numerator a bit more than it is already. Mostly we need to take out a 4. It might seem pointless at first, but once we do it everything will become clear:

$4 y - 8 = 4 \left(y - 2\right)$

Now we can rewrite the problem so it looks like this:

$\frac{4 \left(y - 2\right)}{y + 1} \div \left(y - 2\right)$

Now we can solve it, as we know that
$\frac{y - 2}{y - 2} = 1$

So:
$\frac{4 \left(y - 2\right)}{y + 1} \div \left(y - 2\right) = \frac{4}{y + 1}$

Hope that helps!