Question

How do you find the quotient of `(12n^3-6n^2+15)div6n`?

Answer 1

Quotient is `2n^2-n` and remainder is `15`

Explanation:

`(12n^3-6n^2+15)-:6n`

= `(12n^3)/(6n)-(6n^2)/(6n)+15/(6n)`

= `2n^2-n+15/(6n)`

Hence Quotient is `2n^2-n` and remainder is `15`

Answer 2

`+2n^2-n+15/(6n)`

Explanation:

Note that I am using the place holder of `0n`. It has no value.

`color(white)(.)" "12n^3-6n^2+0n+15`
`color(magenta)(+2n^2)(6n)->" "ul(12n^3" "larr" Subtract")`
`" "0" "-6n^2+0n+15`
`color(magenta)(color(white)(2)-n)(6n)->" "ul(-6n^2" "larr" Subtract")`
`color(magenta)(" "0" "+0n+15" "larr" Remainder")`

`color(magenta)( +2n^2-n+15/(6n))`