How do you find the quotient of #(12n^3-6n^2+15)div6n#?

2 Answers
Jun 12, 2017

Answer:

Quotient is #2n^2-n# and remainder is #15#

Explanation:

#(12n^3-6n^2+15)-:6n#

= #(12n^3)/(6n)-(6n^2)/(6n)+15/(6n)#

= #2n^2-n+15/(6n)#

Hence Quotient is #2n^2-n# and remainder is #15#

Jun 12, 2017

Answer:

#+2n^2-n+15/(6n)#

Explanation:

Note that I am using the place holder of #0n#. It has no value.

#color(white)(.)" "12n^3-6n^2+0n+15#
#color(magenta)(+2n^2)(6n)->" "ul(12n^3" "larr" Subtract")#
#" "0" "-6n^2+0n+15#
#color(magenta)(color(white)(2)-n)(6n)->" "ul(-6n^2" "larr" Subtract")#
#color(magenta)(" "0" "+0n+15" "larr" Remainder")#

#color(magenta)( +2n^2-n+15/(6n))#