How do you find the quotient of #(2x+8)/(x+3)div(x+4)/(x^2+6x+9)#?

1 Answer
Mar 30, 2017

Answer:

# 2 x + 6#

Explanation:

#(2 x + 8)/(x + 3) -: (x + 4)/(x^2 + 6 x + 9)#

change the sign #-:# to * ( multiplication) and change the position of #(x + 4)/(x^2 + 6 x + 9)# to #(x^2 + 6 x + 9)/ (x + 4)#

#= (2 x + 8)/(x + 3) * (x^2 + 6 x + 9)/ (x + 4)#

#= (2(cancel( x + 4)))/cancel((x + 3)) * ((x + 3)cancel((x + 3)))/ cancel((x + 4))#

#= 2(x + 3) = 2 x + 6#