# How do you find the quotient of (4x^2 – y^2) ÷ (2x – y)?

Oct 29, 2015

#### Answer:

$2 x + y$

#### Explanation:

Note that

$\frac{4 {x}^{2} - {y}^{2}}{2 x - y} = \frac{\left(\cancel{2 x - y}\right) \left(2 x + y\right)}{\cancel{2 x - y}} = 2 x + y$

Since ${a}^{2} - {b}^{2} = \left(a + b\right) \left(a - b\right)$

Oct 29, 2015

(2x +y)

#### Explanation:

( 4${x}^{2}$ - ${y}^{2}$) / $\left(2 x - y\right)$

( 4${x}^{2}$ - ${y}^{2}$) can be written as $\left(2 x + y\right) \left(2 x - y\right)$

$\left(2 x + y\right) \left(2 x - y\right) / \left(2 x - y\right)$

$2 x + y$