# How do you find the range of f(x)=3^(x+9)+4?

The range is x in (4;+oo)
The exponential fonction $y = {a}^{x}$ has a range of (0;+oo).
The graph of function $y = {3}^{x + 9} + 4$ is the graph $y = {3}^{x}$ moved $9$ units to the left and $4$ units up. Moving a graph of a function with bounded values up increases the boundaries, so $f \left(x\right)$ has only values greater than $4$.