How do you find the range of #y = t^2 + t - 2#; given Domain = {-2, -1, 0, 1}?

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Answer 1 · 2016-07-07T04:48:42

The accompanying range is given by the y coordinates of the points within the domain.

Substituting:

#(-2)^2 - 2 - 2 = 0#

#(-1)^2 - 1 - 2 = -2#

#0^2 - 0 - 2 = -2#

#(1)^2 - 1 - 2 = -2#

Hence, the range is #{0, -2, -2, -2}#, or #{y| 0, -2, -2, -2}#.

Hopefully this helps!