# How do you find the range of y = t^2 + t - 2; given Domain = {-2, -1, 0, 1}?

Jul 7, 2016

The accompanying range is given by the y coordinates of the points within the domain.

Substituting:

${\left(- 2\right)}^{2} - 2 - 2 = 0$

${\left(- 1\right)}^{2} - 1 - 2 = - 2$

${0}^{2} - 0 - 2 = - 2$

${\left(1\right)}^{2} - 1 - 2 = - 2$

Hence, the range is $\left\{0 , - 2 , - 2 , - 2\right\}$, or $\left\{y | 0 , - 2 , - 2 , - 2\right\}$.

Hopefully this helps!