How do you find the rectangular coordinates given the polar coordinates $(- 1, - \frac{π}{6})$ $(-1, -pi/6)$ ?

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How do you find the rectangular coordinates given the polar coordinates $(- 1, - \frac{π}{6})$ $(-1, -pi/6)$ ?

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Answer 1 · 2016-11-01T23:19:23

Given Polar Coordinates (r,θ), find (rcosθ,rsinθ)
$(- 1 cos (- \frac{π}{6}), - 1 sin (- \frac{π}{6}))$ $(-1cos(-pi/6),-1sin(-pi/6))$
$(- \frac{\sqrt{3}}{2}, \frac{1}{2})$ $(-sqrt3/2,1/2)$

Explanation:

To convert from Polar Coordinates (r,θ) to Cartesian Coordinates (x,y)
$x = r × cos( θ )$
$y = r × sin( θ )$

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How do you find the rectangular coordinates given the polar coordinates $(- 1, - \frac{π}{6})$ $(-1, -pi/6)$ ?

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Explanation:

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How do you find the rectangular coordinates given the polar coordinates $(- 1, - \frac{π}{6})$ $(-1, -pi/6)$ ?