How do you find the reference angle for #(25pi)/4#? Trigonometry Right Triangles Applying Trig Functions to Angles of Rotation 1 Answer Cesareo R. Aug 10, 2016 #pi/4# Explanation: #(25pi)/4 = ((6 xx 4) pi)/4 + pi/4 = 3 xx (2pi)+pi/4# so for functions with minimum period #2pi#, the reference angle is #pi/4# Answer link Related questions How do you determine the values of the six trigonometric functions of the angle if the point... What is the unit circle? How do you find values for the six trigonometric functions for angles of rotation? How do you find sine, cosine, tangent of #90^@# or #180^@# using the unit circle? Why is the unit circle and the trig functions defined on it useful, even when the hypotenuses of... If the point (-5, -12) is a point on the terminal side of an angle in standard position, how do... If #tan theta=2/3# and #cos theta >#, how do you find #sin theta#? In what quadrants will an angle in standard position have a positive tangent value? How is #150^@# related to #30^@# on the unit circle? Question #71ba9 See all questions in Applying Trig Functions to Angles of Rotation Impact of this question 4989 views around the world You can reuse this answer Creative Commons License