How do you find the repeating decimal 0.246 with 246 repeated as a fraction?

1 Answer
Dec 15, 2017

Set the decimal as a variable to be multiplied by a power of ten (such that the repeating decimal part remains the same), then subtract the original from the multiplied number, and simplify as needed to get:
#0.246246246... = 82/333#

Explanation:

Set this repeating decimal to a variable, say, #N#.

#N = 0.246246246...#

Now, multiply this by a power of #10#, one that keeps the decimal part of the number the same:

#1000N = 246.246246246...#

Here, the whole number changes, but what is repeating is still #246#. We can then subtract the original from the multiplied number:

#1000N - N = (246.246246246...) - (0.246246246...)#

The repeating decimals should cancel out:

#999N = 246#

We can finally divide by #999# to get our answer:

#(999N)/999 = 246/999#

#N = 246/999#

And simplify:

#N = 82/333#

Therefore, #0.246246246... = 82/333#