# How do you find the roots, real and imaginary, of y= -5x^2 - 24x  using the quadratic formula?

Jun 9, 2018

;. x= (-b +- b) / (2a) = 0, -b / a = 0, -24/5

#### Explanation:

y = -5x^2 - 24x

$y = a {x}^{2} + b x + c$ is the standard form.

$a = - 5 , b = - 24 , c = 0$

Since c = 0, discriminator $\sqrt{{b}^{2} - 4 a c} = \pm b$

;. x= (-b +- b) / (2a) = 0, -b / a = 0, -24/5#

This can be verified by simplifying the equation

$y = - 5 x \left(x + \frac{24}{5}\right)$