Question

How do you find the second derivative of `(ln(x))^2`?

Answer 1

`f''(x)=(2(1-lnx))/x^2`

Explanation:

As `f(x)=(lnx)^2`

First derivative `f'(x)=2lnx xx1/x=(2lnx)/x`

and second derivative can now be found using quotient rule

`f''(x)=(x xx 2/x-2lnx xx1)/x^2=(2(1-lnx))/x^2`