# How do you find the slant asymptote of y=(x^2)/(2x^2-8)?

No slant asymptote exists, but there is the horizontal asymptote $y = \frac{1}{2.}$
The numerator and denominator are of the same degree (degree $2$) -- no slant asymptote exists in such cases.
Rather, there is a horizontal asymptote given by dividing the coefficients of the leading terms (terms of highest degree), in this case, $y = \frac{1}{2.}$