How do you find the slope and intercept of #4x+2y-5=0#?

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Answer 1 · 2016-02-25T12:43:33

Rearrange the equation to get #m=-2, b=5/2#

The slope-intercept form of a line is given by

#y=mx+b#

where #m# is the slope and #b# is the y-intercept. Our equation needs to be rearranged into this form. We are starting with:

#4x+2y-5=0#

First, we'll move the #4x# and the constant #-5# to the other side (by adding #-4x+5# to both sides):

#2y=-4x+5#

Now, we divide both sides of the equation by #2# to get #y# all by itself:

#y=-2 x+5/2#

By comparing this equation to the slope intercept form we can see that

#m=-2 , b=5/2#