How do you find the slope and intercept of #4x-3y-7=0#?

1 Answer
Jan 30, 2016

Answer:

This answer involves rearranging the equation to make #y# the subject.

The slope #m=4/3# and the y-intercept #b=7/3#.

Explanation:

Slope-intercept form of a line is:

#y=mx+b# where #m# is the slope and #b# is the y-intercept

In this case it is simply the algebra of rearranging #4x-3y-7=0# to make #y# the subject:

#4x-3y-7=0# (add 7 to both sides)
#4x-3y=7# (subtract #4x# from both sides)
#-3y=7-4x# (divide both sides by #-3#)
#y=-(7-4x)/3 =4/3x-7/3#

From the rearranged equation the slope #m=4/3# and the y-intercept #b=7/3#.