# How do you find the slope and intercept of 4x-3y-7=0?

##### 1 Answer
Jan 30, 2016

This answer involves rearranging the equation to make $y$ the subject.

The slope $m = \frac{4}{3}$ and the y-intercept $b = \frac{7}{3}$.

#### Explanation:

Slope-intercept form of a line is:

$y = m x + b$ where $m$ is the slope and $b$ is the y-intercept

In this case it is simply the algebra of rearranging $4 x - 3 y - 7 = 0$ to make $y$ the subject:

$4 x - 3 y - 7 = 0$ (add 7 to both sides)
$4 x - 3 y = 7$ (subtract $4 x$ from both sides)
$- 3 y = 7 - 4 x$ (divide both sides by $- 3$)
$y = - \frac{7 - 4 x}{3} = \frac{4}{3} x - \frac{7}{3}$

From the rearranged equation the slope $m = \frac{4}{3}$ and the y-intercept $b = \frac{7}{3}$.