How do you find the slope and intercept of #x-2y=0#?

1 Answer
Jan 14, 2016

Answer:

Slope #= 1/2#
y-intercept: #0# (i.e. at #(0,color(green)(0))#
x-intercept: #0# (i.e. at #(color(green)(0),0)#

Explanation:

For a linear equation in the general form:
#color(white)("XXX")color(red)(A)x+color(blue)(B)y=C#
the slope is given by the equation:
#color(white)("XXX")m=-color(red)(A)/color(blue)(B)#

In this case
#color(white)("XXX")x-2y=0color(white)("XXX")rArrcolor(white)("XXX")color(red)(1)x+(color(blue)(-2)y) =0#

and therefore
#color(white)("XXX")m=-(color(red)(1)/(color(blue)(-2)))=1/2#

The y-intercept is the value of #y# when #x=color(cyan)(0)#
#color(white)("XXX")(color(cyan)(0)-2y=0) rarr (y=0)#

The x-intercept is the value of #x# when #y=color(orange)(0)#
#color(white)("XXX")(x-2(color(orange)(0))=0) rarr (x=0)#