How do you find the slope and intercept of #x + 2y=3#?

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Answer 1 · 2016-02-24T19:48:03

Rearrange the equation to get #m=-1/2 , b=3/2#

The slope-intercept form of a line is given by

#y=mx+b#

where #m# is the slope and #b# is the y-intercept. Our equation needs to be rearranged into this form. We are starting with:

#x+2y=3#

First, we'll move the #x# to the other side (by subracting #x# from both sides):

#2y=-x+3#

Now we divide both sides of the equation by #2# to get #y# all by itself:

#y=-1/2 x+3/2#

By comparing this equation to the slope intercept form we can see that

#m=-1/2 , b=3/2#