# How do you find the slope and intercept of –x – 8y = –32?

Slope $= - \frac{1}{8}$ x-intercept $= 32$ y-intercept $= 4$
$- x - 8 y = - 32 \mathmr{and} 8 y = - x + 32 \mathmr{and} y = - \frac{1}{8} \cdot x + 4$ So slope$= - \frac{1}{8}$ and y-intercept $= 4$ x-intercept can be obtained by puuting y=0 in the equation. $- x + 32 = 0 \mathmr{and} x = 32$ so x-intercept $= 32$ graph{-1/8*x+4 [-80, 80, -40, 40]}[Ans]