How do you find the slope and intercept to graph #2x - 6y = 12#?

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Answer 1 · 2016-03-22T18:16:04

the slope is #m = 1/3#

the y intercept is #b=-2#
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#2x - 6y =12#

isolate the term variable with #y#
#cancel(2x) -cancel(2x) - 6y =-2x +12#

# - 6y =-2x +12#

Isolate the #y# variable
# ((cancel(-6)y)/cancel(-6)) =(-2x +12)/(-6)#

# y =(-2x +12)/(-6)#

simplify the fraction

#y=1/3x-2#

the slope intercept equation is
#y=mx+b#
where
#m# = the slope and #b# = they intercept

#m = 1/3#

#b=-2#

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