# How do you find the slope and y intercept for  y=-2?

Jul 1, 2015

$y = - 2$
$\textcolor{w h i t e}{\text{XXXX}}$has a slope of $0$ and
$\textcolor{w h i t e}{\text{XXXX}}$a y-intercept of $\left(- 2\right)$

#### Explanation:

The fact that $y = - 2$ has a slope of $0$ follows from the observation that it is a horizontal line.
The y-intercept is the value of $y$ when $x = 0$; since $y = - 2$ for all values of $x$ (including $0$), the y-intercept is $- 2$

Alternately
you could rewrite the equation into slope intercept form:
$\textcolor{w h i t e}{\text{XXXX}}$$y = m x + b$ with a slope of $m$ and a y-intercept of $b$

$y = - 2$ is equivalent to
$\textcolor{w h i t e}{\text{XXXX}}$$y = 0 \cdot x + \left(- 2\right)$ which is slope-intercept form
$\textcolor{w h i t e}{\text{XXXX}}$$\textcolor{w h i t e}{\text{XXXX}}$with slope $0$ and y-intercept $- 2$

Jul 1, 2015

Slope $= 0$
Y-intercept$= - 2$

#### Explanation:

Your equation represents a horizontal line passing through $y = - 2$ with slope equal to zero (it is horizontal so it is neither going up nor down).

Graphically: 