How do you find the slope and y intercept for # y=-2#?

2 Answers
Jul 1, 2015

Answer:

#y=-2#
#color(white)("XXXX")#has a slope of #0# and
#color(white)("XXXX")#a y-intercept of #(-2)#

Explanation:

The fact that #y=-2# has a slope of #0# follows from the observation that it is a horizontal line.
The y-intercept is the value of #y# when #x=0#; since #y=-2# for all values of #x# (including #0#), the y-intercept is #-2#

Alternately
you could rewrite the equation into slope intercept form:
#color(white)("XXXX")##y=mx+b# with a slope of #m# and a y-intercept of #b#

#y=-2# is equivalent to
#color(white)("XXXX")##y = 0*x +(-2)# which is slope-intercept form
#color(white)("XXXX")##color(white)("XXXX")#with slope #0# and y-intercept #-2#

Jul 1, 2015

Answer:

Slope #=0#
Y-intercept#=-2#

Explanation:

Your equation represents a horizontal line passing through #y=-2# with slope equal to zero (it is horizontal so it is neither going up nor down).

Graphically:
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