# How do you find the slope of a line with x-intercept 3 and y-intercept -4?

Jul 19, 2018

The slope is $\frac{4}{3}$.

#### Explanation:

An $x$-intercept is the value of $x$ when $y = 0$, so an $x$-intercept of $3$ can be written as a coordinate on the graph as $\left(3 , 0\right)$.

Likewise, an $y$-intercept is the value of $y$ when $x = 0$, so an $y$-intercept of $- 4$ can be written as a coordinate on the graph as $\left(0 , - 4\right)$

Now we have two points, $\left(3 , 0\right)$ and $\left(0 , - 4\right)$.

To find the slope given two points, we use the formula $\text{rise"/"run}$, or $\frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}}$.

Plug in the given points into the formula:
$\frac{- 4 - 0}{0 - 3} = - \frac{4}{-} 3 = \frac{4}{3}$

Therefore, the slope is $\frac{4}{3}$.

Hope this helps!