How do you find the slope given #x + 2y=3#?

1 Answer
Jan 14, 2017

Convert the equation to the slope-intercept form - see entire explanation below:

Explanation:

To find the slope we need to convert the equation to the slope-intercept form by solving for #y#:

The slope-intercept form of a linear equation is:

#y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b# is the y-intercept value.

#x + 2y = 3#

#x + 2y - color(red)(x) = - color(red)(x) + 3#

#x - color(red)(x) + 2y = - color(red)(x) + 3#

#0 + 2y = -x + 3#

#2y = -x + 3#

#(2y)/color(red)(2) = (-x + 3)/color(red)(2)#

#(color(red)(cancel(color(black)(2)))y)/cancel(color(red)(2)) = -x/2 + 3/2#

#y = -1/2x + 3/2#

With the equation now in slope intercept form we can see the slope is #color(red)(m = -1/2)#