# How do you find the slope intercept form of a line perpendicular to y=3+2x, passing through (4, -1)?

The equation of the line in slope- intercept form is $y = - \frac{1}{2} \cdot x + 1$.
The slope of the line y=2x+3; m=2:.The slope of the perpendicular line is ${m}_{1} = - \frac{1}{m} = - \frac{1}{2}$. The equation of the perpendicular line in slope- intercept form is $y = - \frac{1}{2} \cdot x + c$.The line passes through $\left(4 , - 1\right) \therefore - 1 = - \frac{1}{2} \cdot 4 + c \mathmr{and} c = 1$.Hence the equation of the line in slope- intercept form is $y = - \frac{1}{2} \cdot x + 1$. graph{-1/2x+1 [-10, 10, -5, 5]}[Ans]