How do you find the slope of the line parallel to and perpendicular to #4x-3y=17#?

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Answer 1 · 2017-08-31T10:51:41

Slope of the parallal line is #4/3# and slope of the perpendicular line is #-3/4#

#4x-3y =17 or 3y = 4x-17 or y = 4/3x -17/3#

Slope of the line is # m=4/3 [y=mx+c]#

Slope of parallel lines are equal.

Slope of the parallal line is # m_1=4/3#

Product of slopes of perpendicular lines is #m_2*m=-1#

# m_2 = -1/(4/3) = -3/4#

Slope of the perpendicular line is # m_2=-3/4#