# How do you find the slope of the line parallel to and perpendicular to 4x-3y=17?

Aug 31, 2017

Slope of the parallal line is $\frac{4}{3}$ and slope of the perpendicular line is $- \frac{3}{4}$

#### Explanation:

$4 x - 3 y = 17 \mathmr{and} 3 y = 4 x - 17 \mathmr{and} y = \frac{4}{3} x - \frac{17}{3}$

Slope of the line is $m = \frac{4}{3} \left[y = m x + c\right]$

Slope of parallel lines are equal.

Slope of the parallal line is ${m}_{1} = \frac{4}{3}$

Product of slopes of perpendicular lines is ${m}_{2} \cdot m = - 1$

${m}_{2} = - \frac{1}{\frac{4}{3}} = - \frac{3}{4}$

Slope of the perpendicular line is ${m}_{2} = - \frac{3}{4}$