# How do you find the slope of the line whose equation is 2x – 4y = 10?

Mar 31, 2015

Yo can rearrange your equation and "see" you slope as coeficient of $x$:
isolating $y$ you have:
$y = \frac{1}{2} x - \frac{5}{2}$

So your slope is $\frac{1}{2}$

Mar 31, 2015

The slope of the line is $\frac{1}{2}$.

The equation of a line in slope-intercept form is $y = m x + b$, where $m$ is the slope, $b$ is the y-intercept, and $x$ and $y$ are a point on the line.

In order to determine the slope from the given equation, do the following:

$2 x - 4 y = 10$ (Subtract $2 x$ from both sides.)

$- 4 y = - 2 x + 10$ (Divide both sides by -4.)

$y = \frac{- 2 x}{- 4} + \frac{10}{- 4}$ (Simplify.)

$y = \frac{1}{2} x - \frac{5}{2}$