# How do you find the slope that is perpendicular to the line -5x-3y+8=0?

Aug 26, 2016

The slope of one line and the slope of a line perpendicular to the first line are negative inverses of each other.

#### Explanation:

If Line1 has slope $m = 3$ , then perpendicular Line2 will have slope $m = - \frac{1}{3}$

To find the slope of your line −5x−3y+8=0, let's put the equation in slope-intercept form:

$y = - \left(\frac{5}{3}\right) x + \frac{8}{3}$

So, your line has slope $m = - \frac{5}{3}$.

The slope of a line that is perpendicular to your line above will be the negative inverse, that is:

$\frac{- 1}{- \frac{5}{3}}$ , which equals positive $\frac{3}{5}$ .

(It's the lines that are perpendicular to each other, not the slopes. The slopes are negative inverses.)