# How do you find the slope that is perpendicular to the line y=x-3?

Apr 21, 2017

See the entire solution process below:

#### Explanation:

The equation given in the problem is in slope intercept form. The slope-intercept form of a linear equation is: $y = \textcolor{red}{m} x + \textcolor{b l u e}{b}$

Where $\textcolor{red}{m}$ is the slope and $\textcolor{b l u e}{b}$ is the y-intercept value.

For this problem:

$y = \textcolor{red}{1} x - \textcolor{b l u e}{3}$

Therefore the slope is: $\textcolor{red}{m = 1}$

Let's call the slope of the perpendicular line ${m}_{p}$

The slope of a perpendicular line is: ${m}_{p} = - \frac{1}{m}$

For this problem then:

${m}_{p} = - \frac{1}{1} = - 1$