How do you find the solution to #3cos^2theta-4costheta+1=0# if #0<=theta<360#?

1 Answer
Nov 29, 2016

#0^@, 70^@53, 289^@47, 369^@#

Explanation:

#3cos^2 t - 4cos t + 1 = 0#
Solve the quadratic equation for cos t.
We have: a = 3, b = -4, and c = 1.
Since a + b + c = 0, use shortcut. The 2 real roots are:
cos x = 1 and #cos x = c/a = 1/3#
a. cos x = 1 --> #x = 0^@# or #x = 360^@#
b. #cos x = 1/3# --> Calculator and unit circle give 2 solutions arcs:
#x = 70^@53# and #x = - 70^@53#, or #x = 289^@47# (co-terminal)

Answers for (0, 360):
#0^@, 70^@53, 289^@47, 360^@#