How do you find the square root of a fraction (12/27)?

You get $\frac{2}{3}$
$\sqrt{\frac{12}{27}} = \frac{\sqrt{12}}{\sqrt{27}} =$
$= \frac{\sqrt{4 \cdot 3}}{\sqrt{3 \cdot 9}} = \frac{\sqrt{4} \cancel{\sqrt{3}}}{\cancel{\sqrt{3}} \sqrt{9}} =$
$= \frac{\sqrt{4}}{\sqrt{9}} = \frac{2}{3}$