# How do you find the standard form and slope intercept of a line that passes through (4,1) parallel to y=-5?

$y = - 5$ has a slope of $0$ since the change in $y$ is $0$ regardless of the change in $x$
The equation of the line passing through $\left(4 , 1\right)$ parallel to $y = - 5$ (that is, with slope $= 0$)
is $y = 1$.
$y = 1$ is its "standard form".