How do you find the standard form given x^2-2x-4y-11=0? Precalculus Geometry of a Hyperbola Standard Form of the Equation 1 Answer mimi Dec 12, 2017 y=x^2/4-x/2-11/4 Explanation: STANDARD FORM: y=ax^2+bx+c Make x^2-2x-4y-11=0 look like y=ax^2+bx+c. x^2-2x-4y-11=0 [Add 4 to both sides.] x^2-2x-11=4y [Divide by 4 to isolate y.] x^2/4-(2x)/4-11/4=y [Simplify.] x^2/4-x/2-11/4=y ANSWER: y=x^2/4-x/2-11/4 Answer link Related questions What is the standard form of the equation of a hyperbola? What conic section is represented by the equation (y-2)^2/16-x^2/4=1? What conic section is represented by the equation y^2/9-x^2/16=1? What conic section is represented by the equation x^2/9-y^2/4=1? How can I tell the equation of a hyperbola from the equation of an ellipse? What does the equation 9y^2-4x^2=36 tell me about its hyperbola? What does the equation (x+2)^2/4-(y+1)^2/16=1 tell me about its hyperbola? What does the equation (x-1)^2/4-(y+2)^2/9=1 tell me about its hyperbola? Why is a hyperbola considered a conic section? How do you write the equation of a hyperbola in standard form given Foci: (3,+-2) and... See all questions in Standard Form of the Equation Impact of this question 2218 views around the world You can reuse this answer Creative Commons License