# How do you find the standard form given x^2-2x-4y-11=0?

Dec 12, 2017

$y = {x}^{2} / 4 - \frac{x}{2} - \frac{11}{4}$

#### Explanation:

STANDARD FORM: $y = a {x}^{2} + b x + c$

Make ${x}^{2} - 2 x - 4 y - 11 = 0$ look like $y = a {x}^{2} + b x + c$.

${x}^{2} - 2 x - 4 y - 11 = 0$ [Add $4$ to both sides.]
${x}^{2} - 2 x - 11 = 4 y$ [Divide by $4$ to isolate y.]
${x}^{2} / 4 - \frac{2 x}{4} - \frac{11}{4} = y$ [Simplify.]
${x}^{2} / 4 - \frac{x}{2} - \frac{11}{4} = y$

ANSWER: $y = {x}^{2} / 4 - \frac{x}{2} - \frac{11}{4}$