# How do you find the standard form of #y^2 - 8x + 4y + 12 = 0#?

##### 1 Answer

Nov 10, 2016

#### Explanation:

Rewrite it as

#y^2 +4y +4 = 8x +16 (by adding 4 on both sides)

This represents a horizontal parabola with its vertex at (-2, -2) with axis of symmetry being y=-2