How do you find the sum of the first 18 terms of #7+(-21)+63+(-189)+...#?

1 Answer
Sep 13, 2016

Sum of first #18# terms is #-1743392196#

Explanation:

As here #-21/7=63/(-21)=(-189)/63=-3#, here we have a geometric series with first term as #7# and common ratio as #-3#.

As in a geometric series with first term as #a# and common ration #r#,

sum of first #n# terms is given by #(a(1-r^n))/(1-r)#

Hence, in the given series sum of first #18# terms is given by

#(18xx(1-(-3)^18))/(1-(-3))#

= #(18xx(1-387420489))/4#

= #-(18xx387420488)/4#

= #-18xx96855122#

= #-1743392196#