How do you find the sum of the infinite geometric series given $1/4+1/6+2/18+ ...$ ?

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Answer 1 · 2016-11-13T04:57:02

The sum is $3/4$ .

Use the formula $s_oo = a/(1 - r)$ , where $r = t_2/t_1$ .

$r = t_2/t_1$

$r = (1/6)/(1/4) = 1/6 xx 4 = 2/3$

$:.s_oo = (1/4)/(1 - 2/3)$

$s_oo = (1/4)/(1/3)$

$s_oo = 3/4$

Hopefully this helps!

How do you find the sum of the infinite geometric series given 1/4+1/6+2/18+ ...1/4+1/6+2/18+ ...?