# How do you find the sum or difference of (-3d^2-8+2d)+(4d-12+d^2)?

##### 1 Answer
Feb 8, 2017

See the entire solution process below:

#### Explanation:

First, remove the terms from within the parenthesis being careful to handle to the sign of each individual term correctly:

$- 3 {d}^{2} - 8 + 2 d + 4 d - 12 + {d}^{2}$

Next, group like terms together:

$- 3 {d}^{2} + {d}^{2} + 2 d + 4 d - 12 - 8$

Now, combine like terms:

$- 3 {d}^{2} + 1 {d}^{2} + 2 d + 4 d - 12 - 8$

$\left(- 3 + 1\right) {d}^{2} + \left(2 + 4\right) d - 20$

$- 2 {d}^{2} + 6 d - 20$