Question

How do you find the third term of `(x/3-3/x)^12`?

Answer 1

`66(x^8/3^8)`

Explanation:

Developing the binomial series
`(x/3-3/x)^12=(x/3)^12+¹²C₁(x/3)^11(-3/x)+¹²C₂(x/3)^10(-3/x)^2+.....`
So the third term is `¹²C₂(x/3)^10(-3/x)^2=(12*11)/(1*2)(x^10/3^10)(3^2/x^2)=66(x^8/3^8)`