How do you find the unit vector in the direction of the given vector 6i-2j?

1 Answer
Douglas K.
Oct 29, 2016

#(3sqrt(10)/10)hati - (sqrt(10)/10hatj)# Please read the explanation.

Explanation:

Divide the given vector by the magnitude:

#|6hati - 2hatj| = sqrt(6^2 + (-2)^2) = 2sqrt(10) #

#(6hati - 2hatj)/(2sqrt(10)) = (3sqrt(10)/10)hati - (sqrt(10)/10)hatj)#

Please observe that the magnitude of the resulting vector is 1:

#sqrt((3sqrt(10)/10)^2 + (- (sqrt(10)/10)hatj)^2) = 1#

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