How do you find the unit vector in the direction of #vecu = (2,1,-3)#?

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Answer 1 · 2018-03-15T21:54:19

The unit vector in the direction of any given vector is the vector divided by its magnitude:

#hatu = vecu/|vecu|#

Given #vecu = (2,1,-3)#

#|vecu| = sqrt(2^2+1^2+ (-3)^2)#

#|vecu| = sqrt14#

#hatu= 1/sqrt14(2,1,-3)#

#hatu= sqrt14/14(2,1,-3)#

#hatu= (2sqrt14/14,sqrt14/14,-3sqrt14/14)#