How do you find the unit vector of 5i-12j?

1 Answer
Jul 28, 2016

#5/13i-12/13j#

Explanation:

The normalised vector corresponding to #5i-12j# is #5/13i-12/13j#

To find the normalised vector, divide by the (Euclidean) norm of the vector:

#|| 5i-12j || = sqrt(5^2+12^2) = sqrt(25+144) = sqrt(169) = 13#

So the unit vector in the same direction is:

#1/13(5i-12j) = 5/13i-12/13j#