How do you find the value of a given the points (a,3), (5,-1) with a distance of 5?

1 Answer
Jul 5, 2017

Answer:

See a solution process below:

Explanation:

The formula for calculating the distance between two points is:

#d = sqrt((color(red)(x_2) - color(blue)(x_1))^2 + (color(red)(y_2) - color(blue)(y_1))^2)#

Substituting the values from the points and for the distance in the problem gives:

#5 = sqrt((color(red)(5) - color(blue)(a))^2 + (color(red)(-1) - color(blue)(3))^2)#

We can now solve for #a#:

Squaring both sides of the equation gives:

#5^2 = (sqrt((color(red)(5) - color(blue)(a))^2 + (color(red)(-1) - color(blue)(3))^2))^2#

#25 = (color(red)(5) - color(blue)(a))^2 + (color(red)(-1) - color(blue)(3))^2#

#25 = (color(red)(5) - color(blue)(a))^2 + (-4)^2#

#25 = (color(red)(5) - color(blue)(a))^2 + 16#

#25 = 25 - 10a + a^2 + 16#

#-color(red)(25) + 25 = -color(red)(25) + 25 - 10a + a^2 + 16#

#0 = 0 - 10a + a^2 + 16#

#0 = -10a + a^2 + 16#

#0 = a^2 - 10a + 16#

#0 = (a - 8)(a - 2)#

#(a - 8)(a - 2) = 0#

Now, solve each term for #0#:

Solution 1)

#a - 8 = 0#

#a - 8 + color(red)(8) = 0 + color(red)(8)#

#a - 0 = 8#

#a = 8#

Solution 2)

#a - 2 = 0#

#a - 2 + color(red)(2) = 0 + color(red)(2)#

#a - 0 = 2#

#a = 2#

The solution is: #a# can be either #8# or #2#