# How do you find the value of the discriminant and determine the nature of the roots 9n^2-3n-8=-10?

$f \left(n\right) = 9 {n}^{2} - 3 n - 8 + 10 = 9 {n}^{2} - 3 n + 2 = 0$
$D = {d}^{2} = {b}^{2} - 4 a c = 9 - 72 = - 63 < 0$