How do you find the values of x and y given #[(x+y, 3), (y, 6)]=[(0, 2y-x), (y^2, 4-2x)]#?

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Gió Share
Jan 11, 2017

Answer:

I got:
#x=-1#
#y=1#

Explanation:

For the two matrices to be equal we need that each element of the first to be equal to the correspondent one of the second, or:
#x+y=0#
#2y-x=3#
#y =y^2#
#4-2x=6#

From the last one:
#2x=4-6#
#2x=-2#
#x=-1#
From the first using #x=-1#:
#-1+y=0#
#y=1#

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