# How do you find the values of x and y given [(x+y, 3), (y, 6)]=[(0, 2y-x), (y^2, 4-2x)]?

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#### Explanation:

I want someone to double check my answer

1
Gió Share
Jan 11, 2017

I got:
$x = - 1$
$y = 1$

#### Explanation:

For the two matrices to be equal we need that each element of the first to be equal to the correspondent one of the second, or:
$x + y = 0$
$2 y - x = 3$
$y = {y}^{2}$
$4 - 2 x = 6$

From the last one:
$2 x = 4 - 6$
$2 x = - 2$
$x = - 1$
From the first using $x = - 1$:
$- 1 + y = 0$
$y = 1$

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