# How do you find the vertex and axis of symmetry, and then graph the parabola given by:  y= x^2+ 4x + 3?

Sep 29, 2015

Vertex (-2,-1)

Axis of symmetry x= -2

#### Explanation:

First write the equation by completing the square for x,

$y = {x}^{2} + 4 x + 4 - 1$

$y = {\left(x + 2\right)}^{2} - 1$

$\left(y + 1\right) = {\left(x + 2\right)}^{2}$

In this form, the vertex is given by x+2=0 and and y+1=0, that is (-2, -1). Axis of symmetry is given by the equation x= -2

The graph would look like as follows: