Question

How do you find the vertex and axis of symmetry, and then graph the parabola given by: `y=x^2 +10x-11`?

Answer 1

Graph `y = x^2 + 10x - 11`

Explanation:

x-coordinate of axis of symmetry and vertex:
`x = (-b/2a) = -10/2 = -5`
y-coordinate of vertex:
y = f(-5) = 25 - 50 - 11 = -61
graph{x^2 + 10x - 11 [-80, 80, -40, 40]}