# How do you find the vertex and axis of symmetry, and then graph the parabola given by:  f(x)=(x+2)^2-8?

##### 1 Answer
Sep 27, 2015

Be able to recognize the vertex form of a parabola.

#### Explanation:

The vertex form for a parabola is:

$y = {\left(x - h\right)}^{2} + k$

Where, $\left(h , k\right)$ is the vertex.

In this problem, $h = - 2$ and $k = - 8$

So, the vertex $= \left(- 2 , - 8\right)$

The axis of symmetry passes through the x-coordinate of the vertex:

$x = - 2$

graph{(x+2)^2-8 [-20, 20, -10, 10]}

Hope that helps