Question

How do you find the vertex and axis of symmetry, and then graph the parabola given by: `y=3x^2-9x+5`?

Answer 1

Graph parabola `f(x) = 3x^2 - 9x + 5`

Explanation:

x- coordinate of vertex, or axis of symmetry:
`x = (-b/(2a)) = 9/6 = 3/2`
y-coordinate of vertex:
`y = f(3/2) = 27/4 - 27/2 + 5 = -7/4`
graph{3x^2 - 9x + 5 [-5, 5, -2.5, 2.5]}