How do you find the vertex and axis of symmetry, and then graph the parabola given by: # f(x)= -x^2+4x-1#?

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Answer 1 · 2015-09-29T13:23:06

Vertex #(2,3)#
Axis of Symmetry #x=2#

#f(x) = -x^2+4x-1#

#a=-1;b=4;c=-1#

#x=(-b)/(2a) =(-4)/(2 xx (-1))=2#

At #x=2; f(x) =-(2)^2+4(2)-1#
#f(x) =-4+8-1=3#

Vertex #(2,3)#
Axis of Symmetry #x=2#

Take a few points less than 2 and a few values greater than 2

x: y
-1: -6
0: -1
1: 2
2: 3
3: 2
4: -1
5: -6

graph{-x^2+4x-1 [-10, 10, -5, 5]}