Question

How do you find the vertex and axis of symmetry, and then graph the parabola given by: `f(x)=2x^2-4x+1`?

Answer 1

Graph `f(x) = 2x^2 - 4x + 1`

Explanation:

x-coordinate of axis of symmetry and vertex:
x = ( -b)/2a = 4/4 = 1
y-coordinate of vertex:
f(1 ) = 2 - 4 + 1 = - 1
graph{2x^2 - 4x + 1 [-10, 10, -5, 5]}