Question

How do you find the vertex and the axis of symmetry & graph the function `h(x) = 2x^2 + 16x + 23`?

Answer 1

Vertex is `(-4,-9)` And Axis of symmetry is `x=-4`

Explanation:

`h(x)= 2x^2=16x+23 = 2(x^2+8x+16)+23-32=2(x+4)^2-9`So Vertex is `(-4,-9)` This is an equation of parabola which opens up and the Axis of symmetry is `x=-4` graph{2x^2+16x+23 [-40, 40, -20, 20]}[Ans]