# How do you find the vertex, focus, and directrix of the following parabola and graph the equation #y^2-8y+8x+16=0#?

##### 1 Answer

May 4, 2017

Vertex is

#### Explanation:

or

or

or

Hence vertex is

As coefficient of

As this coefficient is

graph{(y^2-8y+8x+16)(x-2)(y-4)((x+2)^2+(y-4)^2-0.04)=0 [-20.25, 19.75, -6.36, 13.64]}